From the free course AP Physics 1 on Lykke
1.1 Scalars and Vectors in One Dimension
Key concepts: Scalars and vectors in one dimension · Physical quantities · Comparing physical quantities between scenarios or at different times and locations · Representing physical situations with diagrams, tables, charts, or schematics · Applying an appropriate law, definition, or theoretical relation · Science Practice 1 · Science Practice 2 · Science Practice 3
A scalar tells you how much of a physical quantity exists, while a vector tells you both how much and in which direction. A car traveling at $20\ \text{m/s}$ and a car traveling at $20\ \text{m/s}$ in the opposite direction have the same speed but different velocities because velocity includes direction.
1.1 Scalars and Vectors in One Dimension
A scalar tells you how much of a physical quantity exists, while a vector tells you both how much and in which direction. A car traveling at $20\ \text{m/s}$ and a car traveling at $20\ \text{m/s}$ in the opposite direction have the same speed but different velocities because velocity includes direction.
In one dimension, direction can be represented with a sign. Choose one direction as positive—often rightward or upward—and represent the opposite direction as negative. The sign is not an extra physical quantity; it records the vector’s direction relative to the chosen coordinate axis.
Physical quantities: amount versus direction
A physical quantity is a measurable property described by a number and a unit. Some physical quantities are scalars; others are vectors.
| Quantity | Type | Example |
|---|---|---|
| Time | Scalar | $t=4.0\ \text{s}$ |
| Mass | Scalar | $m=2.0\ \text{kg}$ |
| Distance | Scalar | $d=15\ \text{m}$ |
| Speed | Scalar | $v=6.0\ \text{m/s}$ |
| Position in one dimension | Vector-like directed quantity | $x=-3.0\ \text{m}$ |
| Displacement | Vector | $\Delta x=+8.0\ \text{m}$ |
| Velocity | Vector | $v=-5.0\ \text{m/s}$ |
| Acceleration | Vector | $a=+2.0\ \text{m/s}^2$ |
The word vector becomes especially manageable in one dimension because there are only two possible directions along an axis. In two or three dimensions, a vector requires components or an angle; here, a signed number is enough to distinguish opposite directions.
Representing a physical situation
A physical situation becomes easier to reason about when its verbal description is translated into a representation: a diagram, table, chart, or schematic. The representation should make the chosen direction, relevant locations, and measured quantities visible rather than leaving them hidden in prose.
Example: two runners on a straight path. Let east be positive. Runner A is $12\ \text{m}$ east of the starting line, and Runner B is $7\ \text{m}$ west of it.
$$ x_A=+12\ \text{m} $$
$$ x_B=-7\ \text{m} $$
A number-line representation is therefore more informative than two unsigned distances:
$$ \text{west}\qquad\leftarrow\qquad -7\ \text{m}\quad\vert\quad 0\quad\vert\quad +12\ \text{m}\qquad\rightarrow\qquad\text{east} $$
The diagram shows immediately that Runner A is farther east, while Runner B is farther west. It also prevents a common error: treating “$7\ \text{m}$ west” as merely $7\ \text{m}$ and losing the directional information.
Comparing quantities across scenarios
Skill 2.C — Compare physical quantities between two or more scenarios or at different times and locations in a single scenario. Comparison requires identifying both the numerical magnitude and, when applicable, the direction.
Suppose a robot’s position changes from $x_1=-2.0\ \text{m}$ to $x_2=+5.0\ \text{m}$. Its final position has greater magnitude than its initial position:
$$ |x_2|=5.0\ \text{m}>|x_1|=2.0\ \text{m} $$
The robot is also on the opposite side of the origin at the second time. Saying only that “$5.0$ is greater than $2.0$” is incomplete unless the comparison concerns magnitudes. For directed quantities, $+5.0\ \text{m}$ and $-2.0\ \text{m}$ are not simply “larger” and “smaller” versions of the same physical situation; they describe different directions.
Key distinction: A scalar comparison usually concerns magnitude. A vector comparison may require magnitude and direction.
Applying definitions and relationships
Skill 3.B — Apply an appropriate law, definition, theoretical relationship, or model to make a claim. A definition is not just a formula to substitute into; it tells you what physical meaning a calculation represents.
For positions measured along one axis, the displacement definition is
$$ \Delta x=x_f-x_i. $$
For the robot above,
$$ \Delta x=(+5.0\ \text{m})-(-2.0\ \text{m})=+7.0\ \text{m}. $$
The positive result means the robot’s position changed $7.0\ \text{m}$ in the positive direction. This is different from the total distance traveled if the robot changed direction along the way; that distinction becomes important when motion quantities are developed in Topic 1.2.
Science Practice 1: Creating Representations
The course framework uses numbered, color-coded science practices to identify the reasoning emphasized in each lesson. Topics $1.1$ through $1.5$ incorporate Science Practice 1: Creating Representations, Science Practice 2: Mathematical Routines, and Science Practice 3: Scientific Questioning and Argumentation. In this topic, the most direct application is Skill 1.A — Create diagrams, tables, charts, or schematics to represent physical situations.
A strong representation is selective: it includes the coordinate direction, origin, object locations, signs, and units, but does not bury the central relationship under irrelevant decoration. A useful workflow is:
- Choose and label the positive direction.
- Mark the origin or reference location.
- Assign signs to directed quantities.
- Record numerical values with units.
- Use the representation to compare or calculate.
Misconception check
Misconception: “A negative vector means the quantity is less than zero physically.” Negative position, velocity, or displacement does not mean that the object has a negative amount of motion or a negative length. It means the vector points opposite the selected positive direction.
Retrieval check: A cyclist is at $x=+10\ \text{m}$ and later at $x=-4\ \text{m}$. Which position has greater magnitude, and what is the cyclist’s displacement?
The position at $x=+10\ \text{m}$ has greater magnitude because $|+10|>|-4|$. The displacement is
$$ \Delta x=(-4\ \text{m})-(+10\ \text{m})=-14\ \text{m}, $$
so the cyclist moved $14\ \text{m}$ in the negative direction.



Source Materials
- Review the Exam Updates (.pdf)
- AP Physics 1: Algebra-Based Course and Exam Description
- AP Physics 1 Course Overview
- AP Physics 1 Course at a Glance
- AP Physics 1 Course at a Glance Poster
- Adopt AP Physics 1: Algebra-Based
- AP Physics 1: Algebra-Based
- AP Physics 1: Algebra-Based
- 3.B Applyanappropriatelaw,definition,theoreticalrelationship,ormodeltomakeaclaim.
- 2.C Comparephysicalquantitiesbetweentwoormorescenariosoratdifferenttimesand locations in a single scenario.
- AP Physics 1 Past Exam Questions — AP Central
- Khan Academy — AP/College Physics 1